20x^2+2x=6

Solution for 20x^2+2x=6 equation:

20x^2+2x=6

We move all terms to the left:

20x^2+2x-(6)=0

a = 20; b = 2; c = -6;
Δ = b2-4ac
Δ = 22-4·20·(-6)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-22}{2*20}=\frac{-24}{40}
=-3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+22}{2*20}=\frac{20}{40}
=1/2
$